A 15 N force is applied to a 12 kg box for 6 s. The box is initially at rest. What is the speed of the box at the end of the 6 s interval

The speed of the box at the end of the 6 s interval is 7.5 m/s.

Explanation:

Given;

magnitude of the force, f = 15 N

mass of the box, m = 12 kg

initial velocity of the box, u = 0

time of the box motion, t = 6s

The applied force on the box is given by Newton's second law of motion;

f = ma

where;

a is the acceleration of the box

a = f / m

a = (15) / (12)

a = 1.25 m/s²

The final velocity of the box is calculated as;

v = u + at

v = 0 + (1.25 x 6)

v = 7.5 m/s.

Therefore, the speed of the box at the end of the 6 s interval is 7.5 m/s.

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