A soccer player is running to the right at 3.2m/s when a 0.50kg ball travelling at 5.0 m/s to the left collides their 5.0kg head. If the player's head velocity after the collision is 2.5 m/s to the right, what is the new velocity of the ball?

300 m/s

Explanation:

Step one:

Given data

Mass of players head m1= 5kg

The initial velocity of players head u1= 3.2m/s

mass of ball m2= 0.5kg

Initial velocity of ball= 5 m/s

Final velocity of player= 2.5 m/s

Required

The velocity of the ball after collision

Step two:

Applying the conservation of momentum formula for elastic collision

m1u1+m2u2= m1v1+m2v2

substitute

5*32+0.5*5= 5*2.5+0.5*v2

160+2.5= 12.5+0.5v2

collect like terms

162.5-12.5= 0.5v2

150= 0.5v2

divide both sides by 0.5

v2= 150/0.5

v2=300 m/s

The new velocity of the ball is 300 m/s

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.

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