A bottle rocket is fired off and has an acceleration of 14.5 m/s2 for the 2.25s until it burns out. If it starts at rest, what distance does it cover?

S = 16.3125m

Explanation:

Given the following data;

Acceleration, a = 14.5m/s²

Time, t = 2.25secs

Since the bottle rocket starts from rest, its initial velocity is 0m/s.

To find the distance S, we would use the second equation of motion.

S = ut + ½at²

Substituting into the equation, we have

S = 0(2.25) + ½*14.5*2.25

S = 0 + 7.25*2.25

S = 16.3125m

Therefore, the bottle rocket covered a distance of 16.3125 meters.

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