Consider the low-speed flight of a Space Shuttle as it is nearing a landing. If the air pressure and temperature at the nose of the shuttle are 1.05 atm and 300 K, respectively, calculate the density and specific volume. (Round the final answer to two decimal places.) The density is kg/m3. The specific volume is m3/kg.

d = 1.24 kg/m³

v = 0.81 m³/kg

Explanation:

To do this, we need to analyze the given data and know the expressions we need to use here to do calculations.

We have a pressure of 1.05 atm and 300 K of temperature. To determine the density, we need to use a similar expression of an ideal gas. In this case, instead of using moles, we will use density:

P = dRT

d = P/RT  (1)

Where:

R: universal constant of gases

d: density.

From here we can determine the specific volume by using the following expression:

v = 1/d   (2)

Now, as we are looking for density, we need to convert the units of pressure in atm to Pascal (or N/m) and the conversion is the following:

P = 1.05 atm * 1.013x10⁵ N/m atm = 106,365 N/m

Now, using R as 287 the density would be:

d = 106,365 / (287 * 300)

Finally the specific volume:

v = 1 / 1.41

Hope this helps

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

i'm on my way to history not a mistory.