Question 5 (1 point) A particle with charge 3.13 C travels through a magnetic field of strength 0.88 T that
is oriented due south. If it experiences a force of 240.27 N directed upwards, then
what is the magnitude and direction of its velocity? That is, how fast and in what
direction is it going?
(Put the direction as part of your unit, for example: "m northwest" and no, that's not
the answer)
Your
Answer
units

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !