Pls.. me with this i really need it.. pls. a gas in a cylinder expands from a volume of 0.110 m3 to 0.320 m3. heat flows into the gas just rapidly enough to keep the pressure constant at 1.65 x 105 pa during the expansion. the total heat added is 1.15 x 105 j. (a) find the work done by the gas. (b) find the change in internal energy of the gas. (c) does it matter whether the gas is ideal? why or why not?

 a)

At constant pressure, the work done for gas to expand is given by:

W = PΔV

⇒W = 1.65 × 10⁵Pa × (0.320 - 0.110)m³= 3.46 × 10⁴J

b)

The total heat (Q) added to the system is used in work done and the remaining energy goes into internal energy.

ΔU = ΔQ-ΔW

⇒ΔU = 1.15 ×10⁵J - 3.46 × 10⁴J = 0.8 × 10⁵ J

c)

It does not matter that the gas is ideal or real because the work done would remain same. It would vary for real gases only at very high pressure.

momentum of soft ball three times less than baskey ball

a is the best answer your welcome