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a rigid container of o2 has a pressure of 340 kpa at a temperature of 713 k what is the pressure at 273 k? show work
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[p1 ] [ v1 ] / [ t1 ] = [ p2 ] [ v2 ] / [ t2 ]

[ p2 ] = [ p1 ] [ v1 / v2 ] [ t2 / t1 ]

[ p2 ] = [ 340 ] [ 1.000 ] [ 273.0 / 713.0 ] = 130 kpa.

We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 273 x 340 / 713

P2 = 130 kPa

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

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