Light rays from an object after passing through a convex lens form an image at the focal point behind the lens (opposite side of the object). what is the actual position of the object? at the focal point in front of the lens at twice the focal length between the focal point and twice the focal length at a great distance, effectively infinite between the focal point and the lens nextreset

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j