What is the change in the cell voltage when the ion concentrations in the cathode half-cell are increased by a factor of 10?

The change in the cell voltage when the ion concentrations in the cathode half-cell are increased by a factor of 10 is 0.05 v

The standard reduction potentials for iron and silver are as follows:

In the given cell, the oxidation occurs at an anode which is a negative electrode whereas the reduction occurs at the cathode which is a positive electrode.

The given cell reactions are:

Oxidation half reaction (anode):

Reduction half reaction (cathode):  

Then the anode and cathode will be

and  respectively.

The overall cell reaction will be,

To calculate the of the reaction, we use the equation:

Now we have to calculate the cell potential.

Using Nernst equation:

where,

n = number of electrons in oxidation-reduction reaction = 2

= emf of the cell = ?

Now put all the given values then we get:

.

What is the change in the cell voltage when the ion concentrations in the cathode half-cell are increased by a factor of 10?

Hence, The ion concentrations in the cathode half-cell are increased by a factor of 10 from 1 M to 10 M.

The emf of the cell potential will be 10 M.

Using Nernst equation:

Then the change in cell voltage will be:

Thus, the change in the cell voltage when the ion concentrations in the cathode half-cell are increased by a factor of 10 is 0.05 v

Grade:        9

Subject:  chemistry

Chapter:  the change in the cell voltage

Keywords: the cathode,  the cell voltage, half-cell,   the change, the ion concentrations

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