Physics, 13.12.2019 18:31 kyleataylor2005

Two people timed an object with a stop watch . they each got a slightly different result how could this be ?

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They both got slightly different results because as humans we are not that accurate enough to start and stop the stop watches accurate. Plus stop watches are not reliable

Answer from: Tayler9353

This experiment takes two people. ... 2. The second person starts (and stops) the stopwatch without looking at the display. ... something slightly different for each ... Do the times add up or do they start again from zero each time your finger breaks the .
.. Try it and explain the results. Table 1: Mass in Grams. Object. Mass (g).

Answer from: Quest

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.

brainliest if you have proof from k12 test and provide evidence wit image! provide image evi

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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