Physics, 17.09.2019 02:30 isaacgarcia0830

Calculate the freezing point of a solution of 40.0 g methyl salicylate, c7h6o2, dissolved in 800. g of benzene, c6h6. and the freezing point is 5.50°c for benzene. calculate the freezing point of a solution of 40.0 g methyl salicylate, c7h6o2, dissolved in 800. g of benzene, c6h6. and the freezing point is 5.50°c for benzene. 3.41°c -2.09°c 7.59°c 2.09°c

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From the problem statement, we are given a solution thus the solute in the solution would have an effect on some of the properties of the whole system. These properties are called the colligative properties. To calculate the freezing point of the solution, we use the freezing point depression equation which is expressed as follows:

ΔTf = kf(m)i

where ΔTf represents the freezing point depression, kf is a constant which 4.90 C/m for benzene, i is the vant hoff factor which is 1 for the given solute since it does not dissociate into ions and m is the molality of the solution. We calculate as follows:

ΔTf = kf(m)i
ΔTf = 4.90 (40.00 / .800 (122.13)) (1)
ΔTf = 2.01 C

ΔTf = Tf - Tfs
Tfs = 5.5 - 2.01
Tfs = 3.49 C

The correct answer would be the first option.

Answer from: kortetsosie4576

The freezing point of the solution will be 3.9075 $\rm ^\circ C$ .

The freezing point of the solution will be calculated by the formula:

$\rm \Delta T_f\;=\;k_f\;\times\;molality\;\times\;i$

$\rm k_f$ is the constant = 4.90 C/m (benzene), i = von't hoff factor = 1

molality = $\rm \dfrac{weight}{molecular\;weight}\;\times\;mass\;of\;solution$

molality = $\rm \dfrac{40}{152}\;\times\;\dfrac{1000}{800}$

molality = 0.325 m

$\rm \Delta T_f$ = 4.90 $\times$ 0.325

$\rm \Delta T_f$ = 1.5925 $\rm ^\circ C$

The temperature of benzene is $\rm 5.50^\circ C$ and the change in temperature is 1.5925 $\rm ^\circ C$ .

So, the solution temperature will be :

= 5.50 - 1.5925 $\rm ^\circ C$ .

= 3.9075 $\rm ^\circ C$ .

The freezing point of the solution will be 3.9075 $\rm ^\circ C$ .

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Answer from: Quest

it about 600 mph from what i calculated

Answer from: Quest

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic = - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

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Calculate the freezing point of a solution of 40.0 g methyl salicylate, c7h6o2, dissolved in 800. g...

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