Acar accelerates uniformly from rest for a time of 12 sec. the rate of acceleration is 4m/s^2. what is the velocity at the. end of 12 sec?

initial velocity = 0 = v₍i₎

final velocity = ? = v₍f₎

t = 12 sec

Acceleration = 4m/s²

First we have to find the distance d, for this we use the formula,

D = v₍i₎t + 1/2at²

D = 0(12) + ½ (4)(12)²

Distance = d = 288 m

Now to find the Vf use the formula,

V₍f₎² = v₍i₎² + 2ad

V₍f₎² = (0)2 + 2(4)(288)

V₍f₎² = 2304

V₍f₎ = 48 m/s

so the velocity at the end of 12 sec is 48 m/s

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example

15.3 cos 65 degrees trig