An arrow is shot from a height of 1.5 m toward a cliff of height H. It is shot with a velocity of 30 m/s at an angle of 60 degrees above the horizontal. It lands on the top edge of the cliff 4.0 s later. (a) What is the height of the cliff

The height of the cliff is 27.02 m

Explanation:

Given;

height above the ground from which the arrow is shot, h₁ = 1.5 m

initial velocity of the projectile, v = 30 m/s

angle of projection, θ = 60⁰

time taken to reach top of the cliff, t = 4.0 s

The vertical component of the velocity is calculated as;

The height attained by the projectile at the given time is calculated as;

The height of the cliff is calculated as;

H = h₁ + h₂

H = 1.5 m  +  25.52 m

H = 27.02 m

the answer would be   dignified - apex

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.