The density of dry air at room temperature and atmospheric pressure Is 1.2 kg m-3. What volume would 6 kg of dry air occupy under these conditions?​

V = 5 m³

Explanation:

The density of air, d = 1.2 kg/m³

Mass of the dry air, m = 6 kg

We need to find the volume o the gas. We know that, the density of an object is given by mass divided by its volume. So,

So, the volume of the dry air is 5 m³.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

connect the batteries in series and hope