Two children are sliding down a snowy hill which is inclined by 44.6 degrees with respect to horizontal. One has a rough sled which has a coefficient of kinetic friction between it and the snow of μ​k= 0.350; the other has a slippery sled which has a coefficient of kinetic friction between it and the snow of μk= 0.161. If both children start at the top of the 40.4 m tall hill initially at rest, what is the difference in speed between these two sleds at the bottom of the hill?

e) none of the above answers are correct

attach the statements so i can answer : )

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s