About how far apart must you hold your hands for them to be separated by 2.8 nano-light-second (the distance light travels in 2.8 ns)? Assume that the speed of light is 2.998*10^8 m/s.

Ohm's law tells you that i = v/r where v is equivalent voltage and r is equivalent resistance of the circuit
since all circuits have the same voltage, your question is really asking which circuit has the lowest total resistance, since the lower the resistance, the higher the current
circuit a has a resistance of 5 ohms; circuit c is in series so has a resistance of 10 ohms; circuit b is in parallel and therefore has a resistance of 2.5 ohms (review your notes on adding resistances in parallel and series); therefore b has the highest current

B. products  hope it !

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