car accelerates uniformly from 5m/s to 15m/s taking 7.5 seconds. How far did it travel during this period?

Given :-

Initial Velocity (u) = 5 m/s

Final Velocity (v) = 15 m/s

Time (t) = 7.5 seconds

To Find :-

Distance (s) = ?

Solution :-

First of all we will find the acceleration of car :

→ Acceleration = Final Velocity - Initial Velocity ÷ Time

→ Acceleration = 15 - 5 ÷ 7.5

→ Acceleration = 10 ÷ 7.5

→ Acceleration = 1.3 m/s²

Now, by using Second equation of motion we can find distance travelled by the car :

→ s = ut + ½ at²

→ s = 5 × 7.5 + ½ × 1.3 × (7.5)²

→ s = 37.5 + ½ × 1.3 × 56.25

→ s = 37.5 + 1.3 × 28.125

→ s = 37.5 + 29.425

→ s = 66.925 m

Therefore,the distance travelled by the car is 66.925 m.

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