A football player with a mass of 110 kg runs into a stationary tackling sled that has a mass of 250 kg. Both the player and sled move together and come to rest 25 cm from the impact. If the coefficient of kinetic friction between the sled and the ground is 0.50, what was the initial speed of the football player

The big glowy thing is called the sun it is a star in our galaxy and is over 1 million degrees

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.