a ball is thrown with a speed of 100 m/s at a height of 150 m take g equals 9.8 m per second calculate the time of flight, angle of projection, range pls help I don't know how to solve it

Hi there!

Since the ball is thrown with an initial HORIZONTAL velocity, we can treat this as a free-fall situation since the horizontal motion does NOT impact the ball's vertical motion.

We can use the derived kinematic equation:

Plug in the given values:

The angle of projection is 0° because there is no vertical component to the velocity as the initial velocity is purely horizontal.

Range:

We can use the equation:

dₓ = vₓt

displacement (x direction) = velocity (x direction) · time

Used the solved-for time and given velocity:

dₓ = 100 · 5.53 = 553 m

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.