An air puck of mass 0.029 kg is tied to a string and allowed to revolve in a circle
of radius 1.7 m on a frictionless horizontal
surface. The other end of the string passes
through a hole in the center of the surface,
and a mass of 1.5 kg is tied to it, as shown.
The suspended mass remains in equilibrium
while the puck revolves on the surface.
0.029 kg
1.7 m
1.5 kg
What is the magnitude of the force that
maintains circular motion acting on the puck?
The acceleration due to gravity is 9.81 m/s?.
Answer in units of N.
part 2 of 2
What is the linear speed of the puck?
Answer in units of m/s.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂