A 70.7 kg high jumper leaves the ground with a vertical velocity of 6.7 m/s.
How high can he jump? The acceleration
of gravity is 9.8 m/s^2.
Answer in units of m

Hi there!

We can use the following kinematic equation:

vi = initial velocity (6.7 m/s)
vf = final velocity (0 m/s at top of trajectory)

a = acceleration due to gravity (-9.8 m/s²)

d = max height reached (? m)

We can plug in the knowns:

Solve for 'd':

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