Acar traveling initially at 6.4 m/s accelerates uniformly at the rate of 1.1 m/s^2 for a distance of 156m. what is the velocity at the end of the acceleration?

There is a formula that should prove helpful here:

v^2 = v0^2 + 2as,        

where v is the final velocity and v0 is the initial velocity,
a is the acceleration and s is the distance traveled.

Here, v^2 = (6.4 m/s)^2 + 2 (1.1 m/s^2)(156 m)

Multiplying this out, we get velocity = v^2 = 40.96 + 2(1.1)(156)
                                                            v^2 = 40.96 + 343.2 = 384.16

Then the final velocity is sqrt(384.16), or 19.6 m/s

Go to the bathroom and vape

Pe = 1/2k(x)^2  and .05n/m = .05x10^-9m = x