How far away from jupiter for normal earth gravity?

You can use the equation Newton's law of gravitation and solve for R, where R is the distance between the centers of two objects, which will ultimately give us the distance for how far away we will need to be from Jupiter to experience the earth's gravity of 9.81 m/s².

So, some things we know...
Newton's law of gravitation: Fg = G(m₁m₂/R²)
R = √(Gm/Fg)  [solve for R]
G = Gravitational constant = 6.674 x 10⁻¹¹ N·m²/kg²
m = mass of Jupiter = 1.90 x 10²⁷ kg
Fg = force of earth's gravity = 9.81 m/s²

R = √((6.674 x 10⁻¹¹)(1.90 x 10²⁷))/(9.81)
R = 1.1369 x 10⁸ m
or
R = 1.1369 x 10⁵ km

Again, R is equal to the distance from the center of two masses. 
The radius of Jupiter is 7.15 x 10⁷ m or 7.15 x 10⁴ km.
We can then subtract, 7.15 x 10⁷ m from 1.1369 x 10⁸ m and do the same for the variables in km. 

Depending on how the assignment wants you to answer, you can choose from answers below.

Approximate distance from Jupiter's center
R = 1.1369 x 10⁸ m
or
R = 1.1369 x 10⁵ km

Approximate distance from surface of Jupiter
4.219 x 10⁷ m or 4.219 x 10⁴ km

Ithink they do have the same properties just in less quantities i think