On hole nine, richard hit a golf ball. the golf ball weighs 0.20 kg. the acceleration of the ball was 41 m/s2. what was the force of richard's swing?

Well first of all, nothing "weighs" 0.2 kg. 
The "kilogram" (kg) is a unit of mass, not force.

Force = (mass) x (acceleration)

During the short time the ball was in contact with the clubface,
the force on the ball averaged

               (0.2 kg) x (41 m/s²)  =  8.2 newtons  (about  1.84 pounds)  .

After the ball left the clubface, it stopped accelerating.
  

Answerthe force between the charges will be  f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes  two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges:     k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then   

Answerinternal combustion engine fuel;