Aperson whose mass is 72 kg has a momentum of 700 kg/m/s (e) .what velocity must this person be travelling at? (2 sig figs)

From the information given, the mass of the moving body, which in this case is a person, is 72 kg and the momentum 700 kg m/s. we use the formula p = m × v. Where p is momentum, m is the mass and v is the velocity. We need v so we rewrite the equation thus: v = p/m In our case p = 700 and m = 72 v = p/m → v = 700/ 72 → v = 9.72 Therefore the person is travelling at 9.72 m/s

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.