Determine the work done by this force to move the particle along the x axis: from x = 0.0 to x = 10.0m. g

Missing figure and incomplete text.full text of the problem (found on internet): "the force on a particle, acting along the x axis, varies as shown in fig. 6-38. determine the work done by this force to move the particle along the x axis: (a) from x =0.0 to x = 10.0 m; (b) from x = 0.0 to x = 15.0 m."figure:   solution: (a) the work done by the force is the integral of the force along the displacement: therefore, it corresponds to the area below the curve of the force in the figure.between x=0 and x=10.0 m, the work is the area of the first trapezoid, which has bases of 10 and 4 and an height of 400: (b) the total work between x=0 and x=15.0m is the sum of the area of the two trapezoids. however, we must take as negative the area of the second trapezoid, since the force is negative in that region.the area of the second trapezoid, which has bases of 5 and 2 and a height of 200, istherefore, the total work between x=0 and x=15.0m is the difference between the two areas: