Determine the kinetic energy of a 575-kg roller coaster car that is moving with a speed of 16.0 m/s. __ j what is the kinetic energy if the coaster was moving at twice the speed? j the kinetic energy now is times greater.

KE at 16m/s

Givens

m = 575 kg
v = 16 m/s

Formula 

KE = 1/2 m* v^2

KE = 1/2 575 * 16^2
KE = 73600

Second Question

m = 575
v = 32 m/s

KE = 1/2 mv^2
KE = 1/2 575 * 32^2
KE = 294400

Third Question

Ke2 = KE1 * k where k is the number of times greater the second is than the first.
294400 = k * 73600
k = 294400 / 73600
k = 4 So the KE of the second condition is 4 times the first.

No because a circle or pie graph usually shows percentages you'd need a line graph

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