If you weigh 670 n on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 25.0 km ? take the mass of the sun to be m s = 1.99×1030 kg , the gravitational constant to be g = 6.67×10−11 n⋅ m 2 /k g 2 , and the acceleration due to gravity at the earth's surface to be g = 9.810 m/ s 2 .

The weight of an object at the surface of a planet is given by:

where m is the mass and g is the gravitational acceleration, given by

where G is the gravitational constant, M is the planet's mass, and r the radius of the planet.

At Earth's surface, . Since we know the weight of the person at Earth's surface, F=670 N, we can find his mass:


Now we have to calculate the value of g at the surface of the neutron star. The mass of the neutron star is 25 times the Sun's mass:


While its radius is:


Therefore, the value of g at the neutron star surface is


Therefore, the weight of the person at the surface of the neutron star would be

3x + 2x = both people using the same measure of like 5x = x= 25 meters per second. 25ms. it takes them 4 seconds to

The purpose of a lab is to do your "expirements" the importance of the topic is so you can now what the story is about and the last one is because no one is me with my question ( what is 3 over 4 x - 9 = 27 maybe you can )