The air in a tire pump has a volume of 1.50 l at a temperature of 5 degrees celcius. if the temperature is increased to 30 degrees celcius and the pressure remains constant, what is the new volume

The new volume is 1.63 L

Explanation:

Step 1: Data given

A tire pump has a volume of 1.5 L, while the temperature is 5 °C

When the temperature changes to 30 °C, the volume will change as well.

The pressure remains constant.

Step 2: Charles' gas law

Since the pressure is constant we can use the following formula:

V1/T1  = V2/T2

with V1 = the initial volume = 1.5L

with T1 = the initial temperature = 5 °C = 273.15 + 5 = 278.15 Kelvin

with V2 = the final volume = TO BE DETERMINED

with T2 = the final temperature = 30 °C = 273.15 + 30 = 303.15 Kelvin

Step 3: Calculate the new volume

1.5L/ 278.15 Kelvin = V2/303.15 Kelvin

V2 = (1.50L * 303.15 Kelvin) / 278.15 Kelvin = 1.63 L

When the temperature increased from 5°C to 30°C, the volume will change to 1.63 L

it is the most commonly accepted one

50.23 i believe is correct but don't quote me on that.