Question 12 (5 points) during an experiment a student traps 0.1941 g of an unknown gas in a 175.6 ml container at 298.1 k and a pressure of 0.9648 atm. what would be the volume of the gas in ml at stp?

V₂ = 155.2 mL

Explanation:

Given data:

Initial volume =175.6 mL

Initial pressure =0.9648 atm

Initial temperature = 298.1 K

Final temperature = 273 K

Final volume =?

Final pressure = 1 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂  /T₁P₂

V₂ = 0.9648 atm × 175.6 mL × 273 k / 298.1 K× 1 atm

V₂ = 46251.4 atm. k. mL/ 298.1 K× 1 atm

V₂ = 155.2 mL

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.