An aqueous NaClNaCl solution is made using 111 gg of NaClNaCl diluted to a total solution volume of 1.20 LL .Calculate the molality of the solution.

The answer to your question is m = 1.6

Explanation:

Data

mass of NaCl = 111 g

volume of water = 1.2 L

Molality = ?

Formula

Molality = number of moles / volume (L)

Process

1.- Calculate the moles of NaCl

Molecular mass = 23 + 35.5 = 58.5 g

                          1 mol of 58.5 g

                          x           111 g

                          x = (111 x 1) / 58.5

                          x = 1.897 moles of NaCl

2.- Calculate the mass of water

density of water = 997 kg/m³

mass = volume x density

mass = 0.0012 x 997

mass = 1.19 kg

3.- Calculate molality

m = 1.897/1.19

m = 1.6