Determine the mass in units of grams [g] of 0.44 moles [mol] of a new fictitious compound you have developed in the lab. The formula is A3B4C8D9. The components are A, amu=7; B, amu=26; C, amu=40; and D, amu=51.

397.76 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of A₃B₄C₈D₉ = 0.44 mol.

Mass of A₃B₄C₈D₉ =.?

Next, we shall determine the molar mass of A₃B₄C₈D₉. This is illustrated below:

Molar mass of A₃B₄C₈D₉ = (3×7) + (4×26) + (8×40) + (9×51)

= 21 + 104 + 320 + 459

= 904 g/mol

Finally, we shall determine the mass of A₃B₄C₈D₉. This can be obtained as follow:

Number of mole of A₃B₄C₈D₉ = 0.44 mol.

Molar mass of A₃B₄C₈D₉ = 904 g/mol

Mass of A₃B₄C₈D₉ =?

Mole = mass /Molar mass

0.44 = mass /904

Cross multiply

Mass = 0.44 × 904

Mass of A₃B₄C₈D₉ = 397.76 g

Therefore, the mass of A₃B₄C₈D₉ is 397.76 g

i think its 100

i hope this !