2 3

Question 13 (1 point)

Which statement best describes how many chlorine atoms are needed when making

Aluminum chloride?

5

3 chlorine atoms are needed because each chlorine atom accepts one of

Aluminum three valence electrons to obtain a full octet and makes chlorine a

negatively charged anion

9

12

3 chlorine atoms are needed because each chlorine atom accepts one of

Aluminums three valence electrons to obtain a full octet and makes chlorine a

positively charged anion

15

1 chlorine atom is needed because chlorine accepts one electron from

Aluminum to obtain a full octet and makes chlorine a negatively charged anion.

01 chlorine atom is needed because chlorine accepts one electron from

Lontot and molec chlorine positively charged cation

3 chlorine atoms are needed because each chlorine atom accepts one of  Aluminum three valence electrons to obtain a full octet and makes chlorine a  negatively charged anion

Explanation:

How many chlorine atoms are needed when making Aluminium Chloride?

The formular for aluminium chloride is given as; AlCl3

In the compound, Aluminium has a valency of +3 and the three chlorine atoms each have a valency of +1 to make the compound a neutral compound.

That meas we can represent AlCl3 as Al³⁺ and 3Cl⁻

The correct statement is;

3 chlorine atoms are needed because each chlorine atom accepts one of  Aluminum three valence electrons to obtain a full octet and makes chlorine a  negatively charged anion

a is the answer to this question

explanation:

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.