A scientist repeats the Millikan oil-drop experiment in a different galaxy and the charge on the drops is measured in a unit called the electrino (el). The scientist obtains data for four drops. Drop Calculated charge (el)
A 5.52×10−14 el
B 4.14×10−14 el
C 5.06×10−14 el
D 2.76×10−14 el
Given the results of the scientist's experiment, determine the charge on an electron in electrinos.

Given that the charge on an electron is 1.60×10−19 C , determine the conversion factor between electrinos and coulombs.
1 C= ? el

i do not get it   at all

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

d) nh3 give me brainliest