A glass jar contains 1 red, 3 green, 2 blue, and 4 yellow marbles. If you were to pull one marble out after the other, what would be the probability of getting a blue and then a yellow marble?
8% 9%
10% 11%

9%

Explanation:

Data obtained from the question:

Red (R) = 1

Green (G) = 3

Blue (B) = 2

Yellow (Y) = 4

Total = 1 + 3 + 2 + 4 = 10

Probability of getting a blue marble is given by P(B)

Probability of getting a yellow marble is given by P(Y)

Probability of getting a blue followed by a yellow marble is given by P(BY)

From the question given:

If we were to pull one marble out after the other, the probability of getting a blue and then a yellow marble is illustrated below

First pull:

P(B) = 2/10

2nd pull:

The total is 9, therefore P(Y) = 4/9

P(BY) = P(B) x P(Y)

P(BY) = 2/10 x 4/9

P(BY) = 8/90 = 0.09

Multiply by 100 to express in percent

P(BY) = 0.09 x 100 = 9%

Therefore, the probability of getting a blue and then a yellow marble is 9%

hi

explanation:

answer:

yes

explanation: