What is the solution to the given system of equations? y = 4x - 28 y = 1.5x - 18 a. (-12, 4) b. (4, -12) c. (7, 0) d. (7.5, 2)

If both those equations are equal to y, then that means by the transitive property, they are equal to each other. We set them equal to each other and solve for x. 4x - 28 = 1.5x - 18. Subtract 1.5x from both sides to get 2.5x = 10 and x = 4. Now sub that value in for x into one of the original equations to find y: y=4(4)-28 and y = 16 - 28 so y = -12. Your solution to that system is (4, -12), B

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.