1. scott works as a delivery person for a shipping company. the graph shows a linear model for his delivery times on different days. (a) what is the equation of the line, first written in point-slope form and then written in slope-intercept form? show how you determined the equation. (b) based on the linear model, predict how long it initially took scott to deliver his packages. approximately how much did his delivery time decrease per day? if you can

Point slope form: -9 = m(3)

Slope intercept form: y = -3x + 30

At x = 0, his delivery time was 30 minutes. It decreased by 3 minutes per day.

Step-by-step explanation:

We have 2 points to calculate the line.

(3, 21) x1 y1

(6, 12) x2 y2

First, we need to calculate the slope.

m =

m =

m = -3

Point slope form is:

y - y1 = m(x - x1)

So for our case:

-9 = m(3)

And slope intercept form is:

y = mx + b

We need to solve for the y intercept (b)

y = -3x + b --- enter the slope

21 = -3(3) + b --- enter in any point on the line for x and y

21 = -9 + b

b = 30 --- solve for b

Now our slope intercept form of the line is:

y = -3x + 30

At x = 0, his delivery time was 30 minutes. It decreased by 3 minutes per day.

idk bring the function back   im not smart

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v