The perimeter of a rectangle is 64 cm the length is 12cm longer than the width what are the length and the width of the rectangle

Width of 10 cm, length of 22 cm

Step-by-step explanation:

P=2L+2w

64=2(12+w)+2w

64=24+2w+2w

40=4w

10=w

L=12+w

L=22cm

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

49%

step-by-step explanation:

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