to get a linear ODE,
(since that would make 
undefined, which we don't want to happen). Then we are forcing any solution to the ODE to exist on any of the three intervals, 
, 
, or 
, and either the first or third of these can be chosen as the largest interval.
, so that
![\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac{1-x}{1+x}\right]=-\dfrac2{(1+x)^2}](/tpl/images/0047/4540/d47e3.png)
![\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac{1-x}{1+x}y\right]=-1](/tpl/images/0047/4540/3e662.png)
![\displaystyle\int\frac{\mathrm d}{\mathrm dx}\left[\frac{1-x}{1+x}y\right]\,\mathrm dx=-\int\mathrm dx](/tpl/images/0047/4540/547bc.png)
give the largest interval i over which the general solution is defined. explain !
(x^2-1)dy/...
Mathematics, 03.07.2019 19:20 dudedude4096
give the largest interval i over which the general solution is defined. explain !
(x^2-1)dy/dx+2y=(x+1)^2
Answers: 1
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