Find the value of xxx in the triangle shown below.

choose 1
choose 1

(choice a)
a
x= \sqrt{27}x=
27

x, equals, square root of, 27, end square root

(choice b)
b
x=\sqrt{90}x=
90

x, equals, square root of, 90, end square root

(choice c)
c
x= 6x=6x, equals, 6

(choice d)
d
x=12x=12

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well what did you do it matters what you did : )

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.