Una empresa desea contratar 3 nuevos
empleados, pero hay 8 candidatos, 6 de los
cuales son hombres y 2 son mujeres. Si la
seleccion es al azar:
a) 2De cuántas maneras diferentes se pueden
elegir los nuevos empleados?
b) De cuántas maneras distintas se puede
elegir a un solo candidato hombre?
c) De cuántas maneras distintas se puede
elegir por lo menos a un candidato horribre?
Rptas a)56 b)6 c)56

answer: c i think

step-by-step explanation:

.25

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )