The taxiways and runways of a major airport are carefully monitored to expedite takeoffs and landings and to prevent collisions. If a pedestrian or vehicle enters a radiocontrolled surface at an airport without receiving permission, this is called a deviation and incursion. Suppose the mean number of deviations and incursions per year at the Los Angeles International Airport (LAX) is 2. Find the probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which

x is the number of sucesses

e = 2.71828 is the Euler number

is the mean in the given time interval.

Suppose the mean number of deviations and incursions per year at the Los Angeles International Airport (LAX) is 2.

This means that

Find the probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

This is P(X = 3).

18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant

570, the answer is 570, hope it