A. Determine the value of an account in which a person invested $6000 for 12 years at an annual rate of 9% compounded annually (n= 1).

16875.98

Step-by-step explanation:

6000(1+(0.09/1)^1*12 = 16875.98

1648

Step-by-step explanation:

A=p(1+rt)

=6000$(1+(9/100)×12))

=1648.56

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: