What is the polar form of -9-9i√3?

18(cos(4pi/3) + i sin(4pi/3))

Step-by-step explanation:

step 1: find the modulus (|z|=√(a^2 + b^2)

|z|=√((-9)^2+(-9√3)^2)= 81+243= 324 => √324=18

step 2: find the argument using theta =tan^-1 (y/x)

theta=tan^-1((-9√3)/-9) = √3

the tangent value of √3 in the third quadrant has the degree measure of 240 and the radian measure of 4pi/3.

Now put them together!

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.