Match each system of linear equations to the correct description of the solution to the system. y=2x+7y−2x=7y=2x+7\newline y-2x=7y=2x+7
y−2x=7
y+4x=−52y=−8x−20y+4x=-5\newline 2y=-8x-20y+4x=−5
2y=−8x−20
y=−34x−2y=34x+1y=-\frac{3}{4}x-2\ne wline y=\frac{3}{4}x+1y=−
4
3
​
x−2
y=
4
3
​
x+1
DRAG & DROP THE ANSWER
no solutions
infinitely many solutions
exactly one solution

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

step-by-step explanation:

ιт ωαѕ 5¢м вє¢αυѕє 1/4 σf 20 ιѕ 5

αи∂ 5*4=20

нσρє ι ¢συℓ∂ нєℓρ уσυ