A train moving at 40km/h applies brakes so that there is a constant 0.5m/s².find the time taken before the train stops. ​

t = 22.22 s

Step-by-step explanation:

Given that,

The initial speed of the train, u = 40 km/h

Acceleration of the train, a = 0.5 m/s²

Finally, it stops, v = 0

We need to find the time taken by it to stop. using first equation of motion to find it such that,

So, it will take 22.22 seconds to stop.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540