Line pq is parallel to bc and splits ab into lengths of x + 8 and x. the other side, ac, is split into lengths of x + 13 and x + 1. what is the length of ac? image not to scale. a) 12 b) 14 c) 16 d) 18

We will work on the value of x.

(x +8) (x + 1) = x ( x+3)

X² + 9x +8 = x² + 13x

13x - 9x = 8

4x = 8

X= 8/4

X=2

Solve for the length of AC by substituting the

Value of x.

Then: x +13 and x+1

     X+X+ 13+1

     2 +2 +13 + 1

=  18

Line segment AC then is 18.

See attached file for further explanation to this item.

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1