PLEASE HELP ME Find the expected value of the winnings
from a game that has the following
payout probability distribution:
6 8
10
Payout ($) 0 4
Probability 0.5 0.2 0.15 0.1 0.05
Expected Value = [?]
Round to the nearest hundredth.

3.00

Step-by-step explanation:

Given that :

Payout(X) : ___ 0 ___ 4 ___ 6 8 10

Probability (p(x) 0.5 _ 0.2 __0.15 __0.1 ___ 0.05

Expected value :E(X) = ΣX* p(x)

E(X) = (0*0.5) + (4*0.2) + (6*0.15) + (8*0.1) + (10*0.05)

E(X) = 3

Expected value = 3.00

44

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3