Jen invested $3500 into a continuously compounded account with an interest rate of 3.1%. After 9 years, how much money is in the account? Round your answer to the nearest whole number

≈$4607

Step-by-step explanation:

I will assume it's compounded yearly.

Apply the compound interest formula.

A = Total

P = Initial Principle

r = Interest Rate

n = number of interest in every t period

t = number of periods

In the case,

P = 3500

r = 3.1% = 0.031

n = 1

t = 9

Hence,

A ≈ 4607 (nearest whole number)

here is the

mark brainliest pl

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.