Mathematics, 21.07.2019 21:40 09daishagreen
Use the chain rule to find dz/dt. z = xy9 − x2y, x = t2 + 1, y = t2 − 1
Answers: 1
![2t[(t^2-1)^9 -2(t^4-1)]+2t[9(t^2+1)(t^2-1)^8-(t^2+1)^2]](/tpl/images/0117/0779/640b7.png)
![\frac{dz}{dt} = (y^9-2xy)(2t)+(9xy^8-x^2)(2t)\\\frac{dz}{dt} = 2t[(t^2-1)^9 -2(t^4-1)]+2t[9(t^2+1)(t^2-1)^8-(t^2+1)^2]](/tpl/images/0117/0779/a9b24.png)
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Use the chain rule to find dz/dt. z = xy9 − x2y, x = t2 + 1, y = t2 − 1...
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